# Challenging Area of Rectangle Question (Involving a Common Side)

The main aim of this math revision note is to help your child become better at solving PSLE Math area of rectangle question that involves a common side.

This type of area of rectangle questions assesses your child’s understanding and sense of proportion/ratio visually.

Before you read on, you might want to download this entire revision notes in PDF format to print it out for your child, or to read it later.

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## Area of Rectangle Question

The perimeter of rectangle ABCD is 60 cm more than that of rectangle PBCQ. 15% of rectangle ABCD is shaded. Find the length of QC.

Solutions

Therefore, AP and DQ makes up the difference.

AP + DQ = 60 cm

Since AP = DQ

AP = 60 cm ÷ 2 = 30 cm

DQ = 30 cm

Since 15% of the whole rectangle is shaded, we can see that

Shaded area = 15% of total

Unshaded area = 100% – 15% = 85% of total

Since the rectangles share the same breadth, the ratio of the areas and the corresponding lengths will be the same.

15u = 30 cm

1u = 30 cm ÷ 15 = 2 cm

85u = 2 cm × 85 = 170 cm (Answer)

Before you go, you might want to download this entire revision notes in PDF format to print it out for your child, or to read it later.

This will be delivered to your email inbox.

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